A1095 Cars on Campus (30)

摘要
Title: A1095 Cars on Campus (30)
Categories: 差分、时间

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A1095 Cars on Campus (30)

题意

Zhejiang University has 8 campuses and a lot of gates. From each gate we can collect the in/out times and the plate numbers of the cars crossing the gate. Now with all the information available, you are supposed to tell, at any specific time point, the number of cars parking on campus, and at the end of the day find the cars that have parked for the longest time period.

思路

给出每个人的车的出入情况,求一个时间里面有多少车,最长的累加停车时间是多少?
会有进出的噪音数据,取最晚进,最早出的时间,这就是一次的停车时间,然后利用差分,统计车的数量
此题也涉及到时间的转换,以及打印

代码

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# 3.8.19 import
import random
from collections import Counter, defaultdict, deque
from datetime import datetime, timedelta
from functools import lru_cache, reduce
from heapq import heapify, heappop, heappush, nlargest, nsmallest
from itertools import combinations, compress, permutations, starmap, tee
from math import ceil, comb, fabs, floor, gcd, hypot, log, perm, sqrt
from string import ascii_lowercase, ascii_uppercase
from sys import exit, setrecursionlimit, stdin
from typing import Any, Callable, Dict, List, Optional, Tuple, TypeVar, Union

# Constants
TYPE = TypeVar('TYPE')
N = int(2e5 + 10)
M = int(20)
INF = int(1e12)
OFFSET = int(100)
MOD = int(1e9 + 7)

# Set recursion limit
setrecursionlimit(int(2e9))


class Arr:
array = staticmethod(lambda x=0, size=N: [x() if callable(x) else x for _ in range(size)])
array2d = staticmethod(lambda x=0, rows=N, cols=M: [Arr.array(x, cols) for _ in range(rows)])
graph = staticmethod(lambda size=N: [[] for _ in range(size)])


class Math:
max = staticmethod(lambda a, b: a if a > b else b)
min = staticmethod(lambda a, b: a if a < b else b)


class IO:
input = staticmethod(lambda: stdin.readline().strip())
read = staticmethod(lambda: map(int, IO.input().split()))
read_list = staticmethod(lambda: list(IO.read()))
read_mixed = staticmethod(lambda *types: [t(v) for t, v in zip(types, IO.input().split())])


class Std:
pass


# ————————————————————— Division line ——————————————————————

def convert_time(time: str) -> int:
h, m, s = map(int, time.split(":"))
return h * 3600 + m * 60 + s


def convert_index(x: int) -> str:
return f"{x // 3600:02}:{x % 3600 // 60:02}:{x % 60:02}"


n, k = IO.read()
diff_ = Arr.array(0, convert_time("24:00:01"))

map_ = defaultdict(lambda: {
"in": [],
"out": []
})

for _ in range(n):
string, time, status = IO.read_mixed(str, str, str)
map_[string][status].append(time)

max_ = Counter()
max_val = 0

for user, dict_ in map_.items():
in_ = dict_["in"]
out_ = dict_["out"]
res = []

res.extend([(convert_time(item), "in") for item in in_])
res.extend([(convert_time(item), "out") for item in out_])

res.sort(key=lambda x: x[0])

pre_in, pre_out = -1, -1
for index, st in res:
if st == "in":
pre_in = index
if st == "out":
pre_out = index

if pre_in != -1 and pre_out != -1 and st == "out" and index > pre_in:
diff_[pre_in] += 1
diff_[index] -= 1
val = index - pre_in
max_[user] += val
max_val = Math.max(max_val, max_[user])
pre_in, pre_out = -1, -1


for i in range(1, len(diff_)):
diff_[i] += diff_[i - 1]

for _ in range(k):
time = IO.input()
print(diff_[convert_time(time)])

users_ = [user for user in max_.keys() if max_[user] == max_val]
users_.sort()

print(" ".join(users_), convert_index(max_val))
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