3185. 构成整天的下标对数目 II

摘要
Title: 3185. 构成整天的下标对数目 II
Categories: 模运算、哈希表

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3185. 构成整天的下标对数目 II

题意

给你一个整数数组 hours,表示以 小时 为单位的时间,返回一个整数,表示满足 i < j 且 hours[i] + hours[j] 构成 整天 的下标对 i, j 的数目。

整天 定义为时间持续时间是 24 小时的 整数倍 。

例如,1 天是 24 小时,2 天是 48 小时,3 天是 72 小时,以此类推。

思路

两数之和的思想,枚举右,维护左

代码

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'''
Author: NEFU AB-IN
Date: 2024-07-11 16:28:48
FilePath: \LeetCode\3185\3185.py
LastEditTime: 2024-07-11 16:40:51
'''
# 3.8.19 import
import random
from collections import Counter, defaultdict, deque
from datetime import datetime, timedelta
from functools import lru_cache
from heapq import heapify, heappop, heappush, nlargest, nsmallest
from itertools import combinations, compress, permutations, starmap, tee
from math import ceil, fabs, floor, gcd, log, sqrt
from string import ascii_lowercase, ascii_uppercase
from sys import exit, setrecursionlimit, stdin
from typing import Any, Dict, List, Tuple, TypeVar, Union

# Constants
TYPE = TypeVar('TYPE')
N = int(2e5 + 10) # If using AR, modify accordingly
M = int(20) # If using AR, modify accordingly
INF = int(2e9)
OFFSET = int(100)

# Set recursion limit
setrecursionlimit(INF)


class Arr:
array = staticmethod(lambda x=0, size=N: [x() if callable(x) else x for _ in range(size)])
array2d = staticmethod(lambda x=0, rows=N, cols=M: [Arr.array(x, cols) for _ in range(rows)])
graph = staticmethod(lambda size=N: [[] for _ in range(size)])

@staticmethod
def to_1_indexed(data: Union[List, str, List[List]]):
"""Adds a zero prefix to the data and returns the modified data and its length."""
if isinstance(data, list):
if all(isinstance(item, list) for item in data): # Check if it's a 2D array
new_data = [[0] * (len(data[0]) + 1)] + [[0] + row for row in data]
return new_data, len(new_data) - 1, len(new_data[0]) - 1
else:
new_data = [0] + data
return new_data, len(new_data) - 1
elif isinstance(data, str):
new_data = '0' + data
return new_data, len(new_data) - 1
else:
raise TypeError("Input must be a list, a 2D list, or a string")


class Str:
letter_to_num = staticmethod(lambda x: ord(x.upper()) - 65) # A -> 0
num_to_letter = staticmethod(lambda x: ascii_uppercase[x]) # 0 -> A
removeprefix = staticmethod(lambda s, prefix: s[len(prefix):] if s.startswith(prefix) else s)
removesuffix = staticmethod(lambda s, suffix: s[:-len(suffix)] if s.endswith(suffix) else s)


class Math:
max = staticmethod(lambda a, b: a if a > b else b)
min = staticmethod(lambda a, b: a if a < b else b)


class IO:
input = staticmethod(lambda: stdin.readline().rstrip("\r\n"))
read = staticmethod(lambda: map(int, IO.input().split()))
read_list = staticmethod(lambda: list(IO.read()))


class Std:
pass

# ————————————————————— Division line ——————————————————————


class Solution:
def countCompleteDayPairs(self, hours: List[int]) -> int:
# 求出任意不相同的两数相加为24的整数倍的个数
# 全部取余,0的可以提出来,其他的加和为24,
hours = [hour % 24 for hour in hours]

cnt_0 = hours.count(0)
res = (cnt_0 - 1) * cnt_0 // 2

cnt_ = Counter()
for hour in hours:
if not hour:
continue
if cnt_.get(24 - hour):
res += cnt_[24 - hour]
cnt_[hour] += 1
return res


print(Solution().countCompleteDayPairs([12, 12, 30, 24, 24]))
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