1683. 困牛放牧

摘要
Title: 1683. 困牛放牧
Tag: 找规律
Memory Limit: 64 MB
Time Limit: 1000 ms

Powered by:NEFU AB-IN

Link

1683. 困牛放牧

  • 题意

    见原题

  • 思路

    讲的不错的题解:Link

  • 代码

    1
    2
    3
    4
    5
    6
    7
    8
    9
    10
    a, b, c = map(int, input().split())

    if c == a + 2:
    print(0)
    elif b == a + 2 or b + 2 == c:
    print(1)
    else:
    print(2)

    print(max(b - a, c - b) - 1)
使用搜索:谷歌必应百度