摘要
Title: 3293. 风险人群筛查
Tag: 模拟
Memory Limit: 64 MB
Time Limit: 1000 ms

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• 题意
• 思路
• 代码

3293. 风险人群筛查

• 题意

  见原题

• 思路

  模拟即可，看哪些点符合条件

• 代码

  n, k, t, xl, yd, xr, yu = map(int, input().split())
  
  cnt1 = 0 #经过
  cnt2 = 0 #逗留
  
  for i in range(n):
      num = list(map(int, input().split()))
      cnt, flag1, flag2 = 0, 0, 0
      for j in range(0, 2 * t - 1, 2):
          x, y = num[j], num[j + 1]
          if x >= xl and x <= xr and y >= yd and y <= yu:
              cnt += 1
          else:
              cnt = 0
          if cnt >= 1:
              flag1 = 1
          if cnt >= k:
              flag2 = 1
      cnt1 += flag1
      cnt2 += flag2
  
  print(cnt1)
  print(cnt2)